Sunday, 24 June 2012

Solution for Question 3 b January 2011

This question is from January 2011 paper.

The sum of two concurrent forces P and Q is 500N and their resultant is 400. If the resultant is perpendicular to 'P', find P and Q and the angle between P and Q.
Given
R is the Resultant = 400N
P+Q= 500N
R is perpendicular to P.




ALL THE BEST FOR YOUR EXAMINATIONS


Posted by at
Labels:

2 comments:

  1. Unknown28 January 2013 at 12:55

    Hello, you used to write wonderful posts, but the last several posts have been kinda boring… I miss your tremendous posts. Past few posts are just a bit out of track! Embroidered logo blazer

    ReplyDelete
  2. Srikanth Ramesh28 January 2013 at 17:18

    Thanks for your concern, actually last posts were done in few minutes through mobile and I was quite busy on some other issues and I think in future I will not let viewers down with direct posts.
    Thankyou very much

    ReplyDelete

Subscribe to: Post Comments (Atom)